1
|
Write a program to print number from 1 to 10. #include<iostream.h>
#include<conio.h>
int main()
{
int i=1;
while(i<=10)
{
cout<<i<<"\n";
i++;
}
getch();
return 0;
}
|
2
|
Write a program to calculate the sum of first 10 natural number.
#include<iostream.h>
#include<conio.h>
int main()
{
int i=1,sum=0;
while(i<=10)
{
sum+=i;
i++;
}
cout<<"Sum :"<<sum;
getch();
return 0;
}
|
3
|
Write a program to find the factorial value of any number entered through the keyboard. #include<iostream.h>
#include<conio.h>
int main()
{
int n,fact=1;
cout<<"Enter any number : ";
cin>>n;
while(n>=1)
{
fact*=n;
n--;
}
cout<<"Factorial :"<<fact;
getch();
return 0;
}
|
4
|
Two numbers are entered through the keyboard. Write a program to find the value of one number raised to the power of another. #include<iostream.h>
#include<conio.h>
int main()
{
int n,p,r=1;
cout<<"Enter the base number and exponent ";
cin>>n>>p;
for(int i=1;i<=p;i++)
r=r*n;
cout<<"Result :"<<r;
getch();
return 0;
}
|
5
|
Write a program to reveres any given integer number. #include<iostream.h>
#include<conio.h>
int main()
{
int n,t,r,rev=0;
cout<<"Enter any number : ";
cin>>n;
t=n;
while(t>0)
{
r=t%10;
t=t/10;
rev=rev*10+r;
}
cout<<"Reverse of number "<<n<<" is "<<rev;
getch();
return 0;
}
|
6
|
Write a program to sum of digits of given integer number. #include<iostream.h>
#include<conio.h>
int main()
{
int n,t,r,sum=0;
cout<<"Enter any number : ";
cin>>n;
t=n;
while(t>0)
{
r=t%10;
sum+=r;
t=t/10;
}
cout<<"Sum of digits of number "<<n<<" is "<<sum;
getch();
return 0;
}
|
7
|
Write a program to check given number is prime or not.
#include<iostream.h>
#include<conio.h>
int main()
{
int n,flag=0;
cout<<"Enter any number : ";
cin>>n;
for(int i=2;i<n;i++)
{
if(n%i==0)
{
flag=1;
break;
}
}
if(flag==0 && n>1)
cout<<"Number is prime";
else
cout<<"Number is not prime";
getch();
return 0;
}
|
8
|
Write a program to calculate HCF of Two given number. #include<iostream.h>
#include<conio.h>
int main()
{
int dividend, divisor, rem, hcf;
cout<<"Enter two numbers : ";
cin>>dividend>>divisor;
while(rem!=0)
{
rem=dividend%divisor;
if(rem==0)
hcf=divisor;
else
{
dividend=divisor;
divisor=rem;
}
}
cout<<"HCF is : "<<hcf;
getch();
return 0;
}
|
9
|
Write a program to enter the numbers till the user wants and at the end it should display the count of positive, negative and zeros entered. #include<iostream.h>
#include<conio.h>
int main()
{
int n, sum_p=0, sum_n=0, sum_z=0;
char choice;
do
{
cout<<"Enter number ";
cin>>n;
if(n>0)
sum_p++;
else if(n<0)
sum_n++;
else
sum_z++;
cout<<"Do you want to Continue(y/n)? ";
cin>>choice;
}while(choice=='y' || choice=='Y');
cout<<"Positive Number :"<<sum_p<<"\nNegative Number :"<<sum_n<<"\nZero Number :"<<sum_z;
getch();
return 0;
}
|
10
|
Write a program to enter the numbers till the user wants and at the end it should display the maximum and minimum number entered. #include<iostream.h>
#include<conio.h>
int main()
{
int n, max=0, min=32767;
char choice;
do
{
cout<<"Enter number : ";
cin>>n;
if(n>max)
max=n;
if(n<min)
min=n;
cout<<"Do you want to Continue(y/n)? ";
cin>>choice;
}while(choice=='y' || choice=='Y');
cout<<"Maximum Number :"<<max<<"\nMinimum Number :"<<min;
getch();
return 0;
}
|
11
|
Write a program to print out all Armstrong numbers between 1 and 500. If sum of cubes of each digit of the number is equal to the number itself, then the number is called an Armstrong number. For example, 153 = ( 1 * 1 * 1 ) + ( 5 * 5 * 5 ) + ( 3 * 3 * 3 ) #include<iostream.h>
#include<conio.h>
int main()
{
int n,digit1,digit2,digit3;
for(int i=1;i<=500;i++)
{
digit1=i/100;
digit2=i/10 - digit1*10;
digit3=i%10;
if(digit1*digit1*digit1 + digit2*digit2*digit2 + digit3*digit3*digit3 == i)
cout<<i<<endl;
}
getch();
return 0;
}
|
12
|
Write a program to print Fibonacci series of n terms where n is input by user : 0 1 1 2 3 5 8 13 24 ..... #include<iostream.h>
#include<conio.h>
int main()
{
int f=0,s=1,t,n;
cout<<"Enter Number of terms of Series : ";
cin>>n;
cout<<f<<" "<<s<<" ";
for(int i=3;i<=n;i++)
{
t=f+s;
cout<<t<<" ";
f=s;
s=t;
}
getch();
return 0;
}
|
13
|
Write a program to calculate the sum of following series where n is input by user.
1 + 1/2 + 1/3 + 1/4 + 1/5 +…………1/n #include<iostream.h>
#include<conio.h>
int main()
{
int i,n;
float sum=0;
cout<<"Enter the value of n ";
cin>>n;
for(i=1;i<=n;i++)
sum += 1.0/i;
cout<<"Sum : "<<sum;
getch();
return 0;
}
|
14
|
Compute the natural logarithm of 2, by adding up to n terms in the series 1 - 1/2 + 1/3 - 1/4 + 1/5 -... 1/n where n is a positive integer and input by user. #include<iostream.h>
#include<conio.h>
int main()
{
int i,n,sign=-1;
float sum=0;
cout<<"Enter the value of n ";
cin>>n;
for(i=1;i<=n;i++)
{
sign *= -1;
sum += sign*1.0/i;
}
cout<<"log 2 : "<<sum;
getch();
return 0;
}
|
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